for循环
循环输出结果
a="abcdefg"
for i in a:
print(i)
a=['a','b','c']
for i in a:
print(i)打印数字范围
for i in range(6):
print(i)
for i in range(1,6):
print(i)
for i in range(6,1,-1):
print(i)加入else
for i in range(6,1,-1):
print(i)
else:
print("end")加入break,continue
rang=['a','ab','abc']
for i in rang:
if len(i) !=3:
print("继续查")
continue
print("这句不会执行,因为continue")
elif i=="abc":
print("我退出了")
break
print("done")斐波纳契数列 , 两个元素的总和确定了下一个数
n = 10
a, b = 0, 1
for i in range(n):
print(b)
a, b = b, a + b